4x^2+24x=288

Solution for 4x^2+24x=288 equation:

4x^2+24x=288

We move all terms to the left:

4x^2+24x-(288)=0

a = 4; b = 24; c = -288;
Δ = b2-4ac
Δ = 242-4·4·(-288)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-72}{2*4}=\frac{-96}{8}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+72}{2*4}=\frac{48}{8}
=6
$